b^2+10bc+25c^2=0

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Solution for b^2+10bc+25c^2=0 equation:


Simplifying
b2 + 10bc + 25c2 = 0

Reorder the terms:
10bc + b2 + 25c2 = 0

Solving
10bc + b2 + 25c2 = 0

Solving for variable 'b'.

Factor a trinomial.
(b + 5c)(b + 5c) = 0

Subproblem 1

Set the factor '(b + 5c)' equal to zero and attempt to solve: Simplifying b + 5c = 0 Solving b + 5c = 0 Move all terms containing b to the left, all other terms to the right. Add '-5c' to each side of the equation. b + 5c + -5c = 0 + -5c Combine like terms: 5c + -5c = 0 b + 0 = 0 + -5c b = 0 + -5c Remove the zero: b = -5c Simplifying b = -5c

Subproblem 2

Set the factor '(b + 5c)' equal to zero and attempt to solve: Simplifying b + 5c = 0 Solving b + 5c = 0 Move all terms containing b to the left, all other terms to the right. Add '-5c' to each side of the equation. b + 5c + -5c = 0 + -5c Combine like terms: 5c + -5c = 0 b + 0 = 0 + -5c b = 0 + -5c Remove the zero: b = -5c Simplifying b = -5c

Solution

b = {-5c, -5c}

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